çözebilirmisiniz acil!​

Çözebilirmisiniz Acil class=

Cevap :

Selam :)

-3 < x < 0

x yerine gelebilecek sayılar:

=> - 2, - 1

[tex]\color{gold}\texttt{3}^{\color{gold}\texttt{-2 }} \color{gold}\texttt{ = } \frac{\color{gold}\texttt{1}}\color{gold}\texttt{3}^{\color{gold}\texttt{2}}[/tex]

[tex]\color{gold}\texttt{=} \frac{\color{gold}\texttt{1}}\color{gold}\texttt{9}[/tex]

 

[tex]\color{gold}\texttt{3}^{\color{gold}\texttt{-1 }} \color{gold}\texttt{ = } \frac{\color{gold}\texttt{1}}\color{gold}\texttt{3}^{\color{gold}\texttt{1}}[/tex]

[tex]\color{gold}\texttt{=} \frac{\color{gold}\texttt{1}}\color{gold}\texttt{3}[/tex]

Şimdi bu değerlerin toplamını bulacağız:

[tex]\frac{\color{gold}\texttt{1}}{\color{gold}\texttt{9}} \color{gold}\texttt{ + } \color{gold}\texttt{}\frac{\color{gold}\texttt{1}}{\color{gold}\texttt{3}} = \frac{\color{gold}\texttt{4}}{\color{gold}\texttt{9}} \: \\ \color{gold}\texttt{(3)} [/tex]

Cevap D)

[tex]\color{pink}\texttt{@Özu♡}[/tex]

[tex]\color{pink}\texttt{bal'}[/tex]

[tex]\color{red}\colorbox{black}{мєянαвαℓαя} [/tex]

cevap ekte sunulmuştur anlamadığınız yeri sorabilirsiniz

[tex]\color{red}\colorbox{black}{ẞαşαяıℓαя Diℓᴇяim} [/tex]

[tex]\color{Lightskyblue}\colorbox{black}{ @xRyan♡ } [/tex]

[tex]\color{black}\colorbox{pink}{'Bebekimm} [/tex]

Görseli göster Аноним